Hello! Here is the question I need help withAn iron sulphid

Hello! Here is the question I need help with:An iron sulphide contains 36.5% S by mass. The iron sulphide is heated in an atmosphere of pure oxygen, which produces SO2(g) and an iron oxide containing 27.6% by mass.a. write a balance equation for the reaction: my answer= 2FeS + 3O2—> 2SO2 + 2FeOb. If 1.0kg of the iron sulphide reacts with excess oxygen, what is the theoretical yield of the iron oxide?so far I have figured out:1.0 Kg FeS = 1000 g FeS x 1 mol FeS/87.92g Fes= 11.37 mol Fesratio of FeS to FeO= 2:211.37 mol FeS x 2mol FeO/2 mol FeS = 11.37 mol FeOI don’t know how to proceed from here…